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Mar 4 at 14:22 comment added M. Winter Has this also been proven in higher dimensions? For example, if all 3-dimensional faces of a 4-polytope are infinitesimally rigid, is the polytope itself infinitesimally rigid?
Feb 27, 2012 at 0:41 history edited Joseph O'Rourke CC BY-SA 3.0
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Feb 26, 2012 at 21:30 comment added Igor Rivin @Joseph: yes, exactly.
Feb 26, 2012 at 20:37 comment added Joseph O'Rourke @Igor: Oh, I see. Thanks. So that is not a relevant consideration. For example, adding diagonals to a cube face both rigidifies it and makes it non-strictly convex along those new edges.
Feb 26, 2012 at 20:23 comment added Igor Rivin It is easy to see what is meant by a non-strictly convex polyhedron: some edges have dihedral angle of $\pi.$
Feb 26, 2012 at 19:33 history answered Joseph O'Rourke CC BY-SA 3.0