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Dec 28, 2018 at 13:58 answer added Alejandro Alvarez-Socorro timeline score: 0
Feb 26, 2012 at 22:35 answer added Aaron Meyerowitz timeline score: 3
Feb 25, 2012 at 1:00 answer added Andrew D. King timeline score: 6
Feb 24, 2012 at 22:15 comment added Gerry Myerson At the risk of stating the obvious, of course there is an algorithm (assuming $G$ is finite). For each vertex $v$, find its distance to each other vertex; for each vertex $v$, look at the numbers you've worked out and see which one is largest; look at this list of largest numbers, and see which ones are smallest. Perhaps you wanted to ask what the most efficient algorithm is?
Feb 24, 2012 at 13:07 answer added Joseph O'Rourke timeline score: 5
Feb 24, 2012 at 9:50 answer added Balazs timeline score: 2
Feb 24, 2012 at 9:23 history asked Mathsniper CC BY-SA 3.0