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Feb 23, 2012 at 12:45 comment added Karl Schwede Perhaps one should also point out that you can always guarantee that $H$ is irreducible (also by Bertini). You can also guarantee that $H$ is normal I think, so at least $X$ is a Weil divisor on $H$.
Feb 23, 2012 at 12:34 comment added Karl Schwede Parsa, that's true. Or for each point $z$ of $X$, you can find one that is smooth near $z$ (but then they don't glue).
Feb 23, 2012 at 7:27 comment added Parsa Thank you Karl. So what you're saying is that I can find an irreducible hypersurface containing $X$ that is smooth away from $X$, even if $X$ is not a complete intersection?
Feb 23, 2012 at 4:35 history edited Karl Schwede CC BY-SA 3.0
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Feb 23, 2012 at 1:13 history undeleted Karl Schwede
Feb 23, 2012 at 0:42 history deleted Karl Schwede
Feb 22, 2012 at 22:50 history edited Karl Schwede CC BY-SA 3.0
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Feb 22, 2012 at 22:41 history answered Karl Schwede CC BY-SA 3.0