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Feb 26, 2012 at 13:52 history edited Matthias Ludewig CC BY-SA 3.0
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Feb 26, 2012 at 13:50 comment added Matthias Ludewig Ok, I think you are right.
Feb 24, 2012 at 18:00 comment added Yemon Choi I think the gap in this argument comes when you claim that you can patch the extensions to get a map $\widetilde{T}$ which is itself dominated by the original sublinear functional. It is dominated if you restrict it to these $B\times \dots B$ where $B$ is your chosen Hamel basis, but I don't see how that is enough.
Feb 24, 2012 at 7:26 comment added Yemon Choi @Kofi: I have tried to explain my reasoning in a separate "answer" to this question
Feb 23, 2012 at 22:29 comment added Matthias Ludewig @Yemon Choi: I don't understand what you mean by "closed". The Hahn-Banach Theorem is purely algebraic and has nothing to do with topology. @ Matthew: Actually, you are right. It might work, it might not, but it seems to be complicated if possible at all. Therefore I chose another route.
Feb 23, 2012 at 22:26 history edited Matthias Ludewig CC BY-SA 3.0
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Feb 23, 2012 at 9:22 comment added Matthew Daws Also, it's not obvious to me how to extend a multisublinear (whatever precisely this actually means) functional to a tensor product. I mean, this might work, but I suspect the devil is in the detail...
Feb 22, 2012 at 23:09 comment added Yemon Choi Kofi, if E is closed in F then $E\hat\otimes E$ need not be closed in $F\hat\otimes F$ ...
Feb 22, 2012 at 22:57 history edited Matthias Ludewig CC BY-SA 3.0
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Feb 22, 2012 at 21:03 comment added Yemon Choi Could you give details of how the inductive step (adding an additional vector) works in the multisublinear case?
Feb 22, 2012 at 19:38 history answered Matthias Ludewig CC BY-SA 3.0