Timeline for What does it mean to say "almost always" ?
Current License: CC BY-SA 3.0
16 events
when toggle format | what | by | license | comment | |
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Feb 21, 2012 at 9:30 | vote | accept | Julie | ||
Feb 21, 2012 at 7:38 | answer | added | Thierry de la Rue | timeline score: 1 | |
Feb 21, 2012 at 7:28 | comment | added | Dan Petersen | This question still doesn't make sense. You can't have uncountably many disjoint open balls in euclidean space. | |
Feb 21, 2012 at 6:28 | history | edited | Julie | CC BY-SA 3.0 |
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Feb 21, 2012 at 6:21 | history | edited | Neil Strickland | CC BY-SA 3.0 |
LaTeX
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Feb 21, 2012 at 6:19 | answer | added | Neil Strickland | timeline score: 1 | |
Feb 21, 2012 at 6:12 | history | edited | Julie | CC BY-SA 3.0 |
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Feb 21, 2012 at 6:08 | comment | added | Julie | @ David and Yoav. Ah, thanks. I have updated my additional info. | |
Feb 21, 2012 at 4:46 | comment | added | David Feldman | BTW, I don't understand your "Additional info." An open set doesn't contain its boundary?!? Right? | |
Feb 21, 2012 at 4:45 | comment | added | David Feldman | $R^{mxn}$ is $\sigma$−compact so an uncountable open cover has a countable subcover. So you're good, right? | |
Feb 21, 2012 at 4:38 | comment | added | Yoav Kallus | Your additional info imply that $A_j$ is an open set which contains its boundary, making it closed. Did you mean to write that $A_j$ is the closure of an open set? | |
Feb 21, 2012 at 3:39 | history | edited | Julie | CC BY-SA 3.0 |
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Feb 21, 2012 at 3:11 | comment | added | Julie | Thanks for all the comments. I have added some more information to my question. Best, Julie | |
Feb 21, 2012 at 1:51 | comment | added | user9072 | If you allow uncountably many sets just to get what you claim you could make the Ah's singletons. So, by itself this cannot possibly tell much. I am afraid without further details there is not much specufuc to answer. | |
Feb 21, 2012 at 1:48 | answer | added | Gerald Edgar | timeline score: 0 | |
Feb 21, 2012 at 1:42 | history | asked | Julie | CC BY-SA 3.0 |