Timeline for Does $S$ being a free rank-$n$ $R$-algebra imply that $S/R$ is free rank $n-1$?
Current License: CC BY-SA 3.0
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when toggle format | what | by | license | comment | |
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Feb 20, 2012 at 20:41 | history | answered | Eric Wofsey | CC BY-SA 3.0 |