Timeline for Does $S$ being a free rank-$n$ $R$-algebra imply that $S/R$ is free rank $n-1$?
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 20, 2012 at 20:57 | vote | accept | Owen Biesel | ||
| Feb 20, 2012 at 20:37 | history | answered | Angelo | CC BY-SA 3.0 |