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Feb 22, 2012 at 21:20 comment added David Ben-Zvi It seems to me that you are giving an isomorphism of two fiber functors on the same category (a Betti and a de Rham one), hence an identification of two Tannakian groups (the "Betti" and "de Rham" Langlands dual groups)??
Feb 22, 2012 at 17:41 history edited robert CC BY-SA 3.0
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Feb 21, 2012 at 11:53 comment added S. Carnahan Which comparison isomorphism? You need to include more detail in your question if you want people to understand it. Please read the "how to ask" page, and follow the advice that is written there.
Feb 21, 2012 at 10:55 history edited robert CC BY-SA 3.0
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Feb 20, 2012 at 11:32 comment added S. Carnahan The result by Mirkovic and Vilonen has nothing to do with de Rham cohomology. You may take coefficients in any ring.
Feb 20, 2012 at 9:27 history asked robert CC BY-SA 3.0