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Jun 20, 2016 at 12:33 history edited Sean Lawton CC BY-SA 3.0
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Feb 20, 2012 at 17:31 comment added Heinrich Is there a simpler way to look at when $g=x+1/x$? Could you please explain?
Feb 19, 2012 at 16:21 comment added Felipe Voloch Birch and Swinnerton-Dyer, Note on a problem of Chowla, Acta Arith, 5 (1959) 417-423, for value sets of general $g$. But for $x+1/x$ you won't need this.
Feb 19, 2012 at 6:33 comment added Heinrich Thanks Felipe!It really helped. Can you please suggest me a reference to read on this? I was interested in the case when $g(x)=x+\frac{1}{x}$ and $f$ is any polynomial.
Feb 18, 2012 at 21:44 comment added Felipe Voloch Expanding on Donu's comment, $C_g: y^p-y=f(g(x))$ maps to $C: y^p-y=f(x)$ by $(x,y) \mapsto (g(x),y)$. From general theory, it follows that the numerator of the zeta function of $C$ divides the numerator of the zeta function of $C_g$. One can also describe the number of points of $g(\mathbb{F}_q)$ in terms of the Galois group of $g(x)-t$, but the answer will depend a lot on $g$ and to get results about $C$ and $C_g$ you'll need to know whether $f$ and $g$ are related or not. Do you have a specific case that you are interested in?
Feb 18, 2012 at 16:34 comment added Heinrich Yes, but I am looking for solutions over $g(\mathbb{F}_q)$ not over $\mathbb{F}_q$. Please let me know if its still unclear. Thanks!
Feb 18, 2012 at 16:10 comment added Donu Arapura I don't really understand your notation. Is $C_g$ the curve $y^p-y=f(g(x))$? If not, then what?
Feb 18, 2012 at 16:01 history edited Heinrich CC BY-SA 3.0
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Feb 18, 2012 at 14:21 history edited Heinrich
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Feb 18, 2012 at 13:56 history asked Heinrich CC BY-SA 3.0