Timeline for Linearly independent vector fields
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Feb 18, 2012 at 18:38 | comment | added | Will Sawin | Ah. I misunderstood your question to imply something very different. Pietro's answer is correct, mine is not. | |
| Feb 18, 2012 at 9:48 | comment | added | Panagiotis Konstantis | Sorry, I don't understand your answer. Please correct me, if I'm wrong: The flow for $(0,1,e^x)$ starting from the origin is given by $t\mapsto(0,t,t)$. Choose for $C$ the unit cube around the origin. Then for an arbitrary $(x,y,z) \in C$ first I would flow along the flow of $(0,1,e^x)$ ending at $(0,y,y)$, then I would adjust the other coordinates by flowing along the other vector fields, which will not change the y--coordinate. I'm always staying in the the unit cube. What is my mistake? | |
| Feb 18, 2012 at 8:44 | history | answered | Will Sawin | CC BY-SA 3.0 |