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Feb 18, 2012 at 10:15 comment added Jérôme Poineau For ring a power series, it actually follows from Konstantin Ardakov's answer.
Feb 18, 2012 at 10:13 answer added Jérôme Poineau timeline score: 0
Feb 17, 2012 at 9:58 comment added Jérôme Poineau By Bass' theorem, if it is projective it is free, but I'm not sure this helps much. Do you know the answer for rings of power series?
Feb 16, 2012 at 23:09 answer added user91132 timeline score: 4
Feb 16, 2012 at 16:08 history asked David Hansen CC BY-SA 3.0