Timeline for "Converse" of Taylor's theorem
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 31, 2014 at 12:32 | answer | added | Peter Michor | timeline score: 4 | |
| Aug 30, 2014 at 22:51 | answer | added | Gro-Tsen | timeline score: 12 | |
| Aug 20, 2014 at 17:46 | answer | added | Benoit Jubin | timeline score: 5 | |
| Oct 10, 2013 at 9:32 | comment | added | S. Carnahan♦ | @carizio If you want to merge, see mathoverflow.net/help/merging-accounts | |
| Feb 15, 2012 at 13:59 | comment | added | Pietro Majer | right, for instance $f(t):=t^{k+1}\chi_{\mathbb{Q}}(t)$ is $o(t^k)$ for $t\to 0$ but it is only differentiable at $0$. | |
| Feb 15, 2012 at 13:14 | comment | added | Gerald Edgar | Also, I seem to recall that is is important that these are functions on a whole interval. Doing this at one point is not enough to show the function is $k$ times differentiable at that point. | |
| Feb 15, 2012 at 11:28 | comment | added | Deane Yang | Yes, I spoke too soon. Nice answer by Pietro. | |
| Feb 15, 2012 at 11:10 | vote | accept | Mizar | ||
| Feb 15, 2012 at 10:49 | comment | added | Mizar | I know, but there nobody could answer. Btw yes, if $k\ge 1$, it is easy to check that $f$ is of class $C^1$. | |
| Feb 15, 2012 at 10:48 | answer | added | Pietro Majer | timeline score: 21 | |
| Feb 15, 2012 at 9:10 | comment | added | Deane Yang | This question is really more suitable for math.stackexchange.com than here. | |
| Feb 15, 2012 at 9:09 | comment | added | Deane Yang | Have you tried doing this for $k = 0$ and $k = 1$? | |
| Feb 15, 2012 at 9:03 | history | asked | Mizar | CC BY-SA 3.0 |