Timeline for partition into the orbits of a dynamical system
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Feb 13, 2012 at 4:49 | comment | added | Vaughn Climenhaga | I'm delighted to see those notes being useful! @Stéphane: I've taken the liberty of fleshing out the consequences of your comments in another answer, as much to remind myself of the details of this as anything else. | |
| Feb 12, 2012 at 15:42 | comment | added | Jon Bannon | Great! I'm glad I could help. | |
| Feb 12, 2012 at 15:30 | vote | accept | Stéphane Laurent | ||
| Feb 13, 2012 at 8:40 | |||||
| Feb 12, 2012 at 15:30 | comment | added | Stéphane Laurent | Thanks, very nice notes ! I believe these notes provide all the answers to my questions. If I well understand, the argument which shows that the orbit partition of an ergodic $T$ is nonmeasurable can be applied to see that ergodicity is not a necessary condition for nonmeasurability: whenever a nonergodic $T$ has more than one orbit in an ergodic component, its orbit partition is nonmeasurable. | |
| Feb 12, 2012 at 15:03 | history | edited | Jon Bannon | CC BY-SA 3.0 |
added 23 characters in body; added 5 characters in body; added 7 characters in body; added 217 characters in body
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| Feb 12, 2012 at 14:54 | history | answered | Jon Bannon | CC BY-SA 3.0 |