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when toggle format what by license comment
Feb 10, 2012 at 15:29 comment added B R I hadn't thought of that, excellent point!
Feb 10, 2012 at 10:31 comment added Peter Humphries And of course the functional equation implies that $P(q^{-1}) = q^{-g} P(1) = q^{-g} h_F$, where $g$ is the genus of the underlying curve and $h_F$ is the class number of $F$.
Feb 9, 2012 at 7:22 history edited B R CC BY-SA 3.0
Changed an incorrect minus to a correct plus.
Feb 9, 2012 at 3:14 history answered B R CC BY-SA 3.0