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Mar 19, 2012 at 15:02 comment added zapkm ohh sorry.. i got.. and thanks for the time...
Mar 19, 2012 at 14:38 comment added Mohan Ramachandran contd:the polynomials referred to are holomorphic.
Mar 19, 2012 at 14:36 comment added Mohan Ramachandran You are confusing approximation and extension. You can certainly approximate f on K uniformly by polynomials .In your example this is easy to do directly .
Mar 19, 2012 at 11:52 comment added zapkm May be i am making mistake.. Please have the following example: Take K any smooth curve which doesn't passes through $(0,0)∈\mathbb C$. Take $f(z)=\frac{1}{z}$, on K, f is continuous, and $\mathbb C−K$ is connected. But f can't be extended to a entire function.... So the theorem you mention seems to have some problem.
Feb 8, 2012 at 21:19 comment added Mohan Ramachandran Yes but the poles of the rational function are outside a neighbourhood of gamma .
Feb 8, 2012 at 19:50 vote accept zapkm
Feb 8, 2012 at 19:50 comment added zapkm Thanks for the answer: But i didn't see this extended version of Hartogs-Rosenthal theorem: I thought that theorem guarantees for the approximation by RATIONAL function. It will be very helpful for me if you can provide some reference. Thanks a lot.
Feb 8, 2012 at 19:02 history answered Mohan Ramachandran CC BY-SA 3.0