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Timeline for Property Sigma Algebra

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Feb 4, 2012 at 0:52 comment added Joel David Hamkins Yes, Gerald, I had in mind just the case $\mathbb{R}\times\mathbb{R}$. But for the general case, one can use the same idea with $\Delta\times\mathbb{R}^{n-1}$, which is a closed subset of $\mathbb{R}\times\mathbb{R}^n$, whose complement is therefore in the OP's collection, but the set itself is not for similar reasons to what I say in my answer.
Feb 3, 2012 at 15:15 comment added Gerald Edgar This is a good idea ... "diagonal" does not quite make sense for $\mathbb R \times \mathbb R^n$, though.
Feb 3, 2012 at 13:36 history answered Joel David Hamkins CC BY-SA 3.0