Timeline for Spectrum of the operator PAP, with A self-adjoint and P strictly positive
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jun 8, 2018 at 12:12 | answer | added | syg | timeline score: 0 | |
Feb 20, 2012 at 21:17 | vote | accept | Peter F | ||
Feb 2, 2012 at 21:17 | comment | added | Helge | Simplest condition $P = P^{-1}$. (So $P = g(Q)$ for $g$ taking values in $+1, -1$.) Note, this condition corresponds to preserving eigenvalues & eigenfunctions. Of course one can imagine many other reasons for the claim to hold ... in the form stated it is just TOO general to handle. | |
Feb 2, 2012 at 17:16 | answer | added | Robert Israel | timeline score: 0 | |
Feb 2, 2012 at 15:54 | comment | added | Matthias Ludewig | Shouldn't a polar decomposition help here? | |
Feb 2, 2012 at 15:19 | history | asked | Peter F | CC BY-SA 3.0 |