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May 6, 2012 at 21:20 answer added Lior Bary-Soroker timeline score: 2
May 6, 2012 at 15:45 answer added John Wiltshire-Gordon timeline score: 6
May 6, 2012 at 6:45 answer added Lior Bary-Soroker timeline score: 3
Feb 3, 2012 at 18:40 vote accept John Pardon
Jan 31, 2012 at 19:19 comment added JSE "right" ==> "write." Why oh why can't we edit comments?
Jan 31, 2012 at 2:32 comment added JSE Andy's answer is a good one and proves that the map you right down actually IS injective. The natural map which is NOT injective is the one from the profinite completion of F_2 to the inverse limit you write down.
Jan 30, 2012 at 22:48 comment added Will Sawin The obstruction isn't that there are elements not contained in any subgroup with a finite solvable quotient. The problem is that each subgroup with a finite solvable quotient contains elements that are not in the kernel of $A_5$. You can keep reducing the number, but there will always be infinitely many. You might get a kernel if you take the profinite completion, though.
Jan 30, 2012 at 22:37 answer added Andy Putman timeline score: 20
Jan 30, 2012 at 22:33 history asked John Pardon CC BY-SA 3.0