Timeline for measuring $n\ 2$-planes in $\mathbb{R}^{2n}$
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| S Jan 24, 2017 at 7:49 | history | suggested | Hee Kwon Lee | CC BY-SA 3.0 |
dollar is needed for math expression in the title
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| Jan 24, 2017 at 7:09 | review | Suggested edits | |||
| S Jan 24, 2017 at 7:49 | |||||
| Mar 13, 2012 at 0:49 | answer | added | Victor Dods | timeline score: 0 | |
| Jan 30, 2012 at 17:30 | comment | added | JHM | Nothing is lost in supposing that $e_1, \ldots f_n$ span a volume 1 parallelopiped. Then their n-volume in $\wedge^2$ will correspond to $|e_1 \wedge \ldots \wedge f_n|$ (ie =1). For fun, in light of the identity dim$Gr_{2,2n}=(2n-2).2=(4n-4).1=$dim$Gr_{1, 4n-3}$ we might try to find a suitable embedding from the Grassmannian of 2-planes in $\mathbb{R}^{2n}$ into $\mathbb{R}P^{4n-3}$ and then take the volume form there. But i don't think this is to be taken seriously. | |
| Jan 30, 2012 at 0:25 | comment | added | Mariano Suárez-Álvarez | The $n$-volume in $\Lambda^2\mathbb R^{2n}$ of the parallelopiped with sides $e_i\wedge f_i$? | |
| Jan 30, 2012 at 0:15 | answer | added | Matt Noonan | timeline score: 1 | |
| Jan 29, 2012 at 21:25 | answer | added | Victor Dods | timeline score: 1 | |
| Jan 29, 2012 at 20:23 | history | edited | JHM |
edited tags
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| Jan 29, 2012 at 20:11 | history | asked | JHM | CC BY-SA 3.0 |