Timeline for Algorithm on winning strategy of Winner (Simplified card game)
Current License: CC BY-SA 3.0
12 events
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| Apr 13, 2017 at 12:32 | history | edited | CommunityBot |
replaced http://cstheory.stackexchange.com/ with https://cstheory.stackexchange.com/
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| Sep 13, 2013 at 18:26 | history | edited | Peter Shor | CC BY-SA 3.0 |
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| Jun 23, 2012 at 5:17 | history | edited | user20948 | CC BY-SA 3.0 |
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| Jun 20, 2012 at 13:14 | history | edited | user20948 | CC BY-SA 3.0 |
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| Jan 31, 2012 at 14:16 | history | edited | user20948 | CC BY-SA 3.0 |
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| Jan 31, 2012 at 6:29 | history | edited | user20948 | CC BY-SA 3.0 |
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| Jan 31, 2012 at 3:53 | history | edited | user20948 | CC BY-SA 3.0 |
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| Jan 31, 2012 at 3:48 | history | edited | user20948 | CC BY-SA 3.0 |
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| Jan 28, 2012 at 7:51 | comment | added | Guillaume Brunerie | And the notation $w(i,A,B)$ means that the card on the table is numbered $i$ (or $0$ if there is no card on the table), that my hand is $A$ and that the hand of the other player is $B$ (and I think that it is $A$ that should be known to the player, unless I’ve understood the rules in the wrong way) | |
| Jan 28, 2012 at 7:45 | comment | added | Guillaume Brunerie |
Just a little reformulation in natural language of the rules : there are two players A and B. Each player has a set of cards (a subset of $\{1,\dots,n\}$) and the aim of the game is to get rid of its own cards. The first player plays any card on the table, then the other player must play a (strictly) bigger card, and so on until one of the players cannot play or decides to pass. Then the cards on the table are discarded, and the other player start again by playing any card (which will be followed by a bigger card). And so on until one of the two players run out of cards and win the game.
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| Jan 28, 2012 at 7:37 | answer | added | Guillaume Brunerie | timeline score: 1 | |
| Jan 28, 2012 at 6:38 | history | asked | user20948 | CC BY-SA 3.0 |