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Jan 28, 2012 at 10:24 comment added Wolfgang Thank you. That's about what I expected: that one of the necessary conditions is essentially sufficient. Like Noam D. Elkies, I didn't really expect there to be any hope of deriving anything directly from a generating function. Let alone the even more hopeless question: If only $g(t,z)$ is given, is there even a way to know, without doing a Taylor expansion, that the coefficients will actually be polynomials in $z$?
Jan 28, 2012 at 10:11 vote accept Wolfgang
Jan 27, 2012 at 23:13 history answered Henry Cohn CC BY-SA 3.0