Skip to main content
9 events
when toggle format what by license comment
Jan 31, 2012 at 22:47 comment added SCL IF $\theta$ in the system above is bounded (e.g. between 0 and $2\pi$) then we can substitute $cos(\theta)$ with $w$ and $\sin(\theta)$ with $z$ and add an additional constraint $z^2 + w^2 = 0$. In this way we can solve the system with known methods for polynomial systems solving (e.g. cylindrical algebraic decomposition).
S Jan 28, 2012 at 17:00 vote accept SCL
Jan 28, 2012 at 17:00 vote accept SCL
S Jan 28, 2012 at 17:00
Jan 27, 2012 at 23:45 answer added zeb timeline score: 2
Jan 27, 2012 at 22:57 vote accept SCL
Jan 28, 2012 at 17:00
Jan 27, 2012 at 21:54 history edited SCL
edited tags
Jan 27, 2012 at 18:47 answer added Sidney Raffer timeline score: 1
Jan 27, 2012 at 18:02 comment added zeb This is at least as hard as 0-1 integer programming - if you set cos(x) = 0, then (1+sin(x))/2 is either 0 or 1...
Jan 27, 2012 at 17:56 history asked SCL CC BY-SA 3.0