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Jan 25, 2012 at 18:16 comment added Jeffrey Adams You also need $\mathbb C^*$ factors
Jan 25, 2012 at 13:52 answer added Hugo Chapdelaine timeline score: 1
Jan 25, 2012 at 13:45 vote accept Hugo Chapdelaine
Jan 24, 2012 at 21:51 history edited Hugo Chapdelaine
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Jan 24, 2012 at 21:39 answer added Jim Humphreys timeline score: 1
Jan 24, 2012 at 21:22 history edited Hugo Chapdelaine CC BY-SA 3.0
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Jan 24, 2012 at 20:52 answer added algori timeline score: 5
Jan 24, 2012 at 19:25 history edited Hugo Chapdelaine CC BY-SA 3.0
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Jan 24, 2012 at 19:25 comment added Hugo Chapdelaine So my maximal $\mathbf{R}$-tori will look like $(\mathbf{R}^{\times})^n\times (S^1)^m$ where $S^1$ stands for the unit circle. May be also I should have restricted my question to real algebraic reductive group
Jan 24, 2012 at 19:22 comment added Hugo Chapdelaine By an $\mathbf{R}$-torus I mean the $\mathbf{R}$-valued points of an algebraic group $H$ defined over $\mathbf{R}$ such that $H\otimes_{\mathbf{R}}\mathbf{C}\simeq (\mathbb{G}_m/\mathbf{C})^n$. So for example, with a rank $1$ torus (case $n=1$), if $T$ is split then $H(\mathbf{R})\simeq \mathbf{R}^{\times}$ and if it is non-split (and non-empty) it is isomorphic to $SO(2)$.
Jan 24, 2012 at 19:10 comment added algori Hugo -- what kind of tori do you have in mind? I.e., do you mean compact tori or products of $\mathbb{R}^*$'s or something else?
Jan 24, 2012 at 18:54 history edited Hugo Chapdelaine CC BY-SA 3.0
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Jan 24, 2012 at 18:30 history asked Hugo Chapdelaine CC BY-SA 3.0