Timeline for Generating function related to 2-residues of partitions
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Nov 17, 2017 at 13:20 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Oct 18, 2017 at 12:57 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 18, 2017 at 12:22 | answer | added | Zhou | timeline score: 2 | |
| Apr 1, 2012 at 18:12 | comment | added | Benjamin Young | why does partial differentiation fail, exactly? It looks like the operator $2y \frac{d}{dy} - 2x \frac{d}{dx} + 1$ might recover your generating function. | |
| Jan 25, 2012 at 16:00 | history | edited | John Murray |
Added some tags
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| Jan 25, 2012 at 11:04 | comment | added | Bernikov | $P(x)=\prod_{i=1}^\infty(1−x^i)^{−1}$ is the partition generating function. | |
| Jan 25, 2012 at 10:52 | history | edited | John Murray | CC BY-SA 3.0 |
Added definition of $P(x)$.
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| Jan 24, 2012 at 17:00 | history | asked | John Murray | CC BY-SA 3.0 |