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Oct 3, 2018 at 1:47 vote accept John Pardon
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jan 24, 2012 at 14:00 answer added Nicola Ciccoli timeline score: 8
Jan 24, 2012 at 5:30 comment added Alexander Chervov By the way, what are finite-dim irreps of $Q_q(GL)$ for q^n=1 ? If we take elements from the same column - they are q-commuting xy=qyx so as a reperesentation we can take 'shift' and 'FT(shift)'. Can we say something interesting about FT (Fourier transform) from quantum groups point of view ?
Jan 24, 2012 at 5:26 comment added Alexander Chervov I think that if you take in $Q_q(G)$ elements of the form $X^n$ they form an ideal. Small check - if I take elements from the same column of $Q_q(GL)$ they are q-commuting variables xy=qyx (well-known), so x^n , y^n are central in column-subalgebra. However "duality O(G) and U(g)" is somewhat subtle - it requires completions - since U(g) - is "delta function at identity for O(G)"... These completions may not well respect q^n=1... So whether it is true that "(the set of elements annihilated by ..." - I am not sure
Jan 24, 2012 at 0:34 history asked John Pardon CC BY-SA 3.0