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Jan 25, 2012 at 8:24 comment added GH from MO @Noam: You are absolutely right, I don't know how I missed that. I also posted a supplement to your answer.
Jan 25, 2012 at 8:23 answer added GH from MO timeline score: 7
Jan 24, 2012 at 20:35 vote accept emiliocba
Jan 24, 2012 at 16:16 answer added Noam D. Elkies timeline score: 16
Jan 24, 2012 at 15:51 comment added Noam D. Elkies @GH There are no cusp forms here. In any case I think if the form is unique in its genus the theta function must be in the Eisenstein subspace.
Jan 24, 2012 at 5:02 comment added GH from MO @Noam: You have a point, but if we decompose spectrally (into Hecke eigenforms) we might get a contribution from cusp forms which is probably not so simple to describe. On the other hand the level is small here, so there might be no cusp forms at all.
Jan 24, 2012 at 0:20 answer added Greg Martin timeline score: 4
Jan 23, 2012 at 22:49 comment added Noam D. Elkies @emiliocba: As usual I don't know a reference, and it would be easier to (re)construct the formula than to locate it in the literature. If you already know the formula it's just a matter of checking that it gives rise to a modular form in the appropriate space and that this space is small enough that there a unique candidate form. If not, itshould be possible to surmise the formula from the first few dozen coefficients of the theta function $\left(\sum_{x,y\in\bf Z} q^{x^2+xy+y^2}\right)^3$.
Jan 23, 2012 at 18:40 history edited emiliocba CC BY-SA 3.0
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Jan 23, 2012 at 18:15 comment added emiliocba Thank Noam, I had not been able to explain it. Do you know some reference in where this formula "could be"?
Jan 23, 2012 at 17:42 comment added Noam D. Elkies @GH: True, but here the number of variables is even, so the theta function is a modular form has integral weight and the formula for its coefficients should be reasonably simple.
Jan 23, 2012 at 17:30 comment added GH from MO It is not clear what you mean by "formula". For example, the quadratic form $x^2+y^2+z^2$ is also alone in its genus, but there is no simple way to determine the number of representations $x^2+y^2+z^2=k$. There is a formula involving class numbers and the square part of $k$, but it only connects two subtle quantities, neither of which is simpler than the other.
Jan 23, 2012 at 15:29 history asked emiliocba CC BY-SA 3.0