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Jan 20, 2012 at 22:13 comment added Karl Waugh I see. My answer was to the similar question of "all even values being minima and all odd values maxima" rather than all minima being even. I still believe you could adjust the idea, considering the probability of each even point being either a minima or a 'through point'
Jan 20, 2012 at 16:53 comment added Liviu Nicolaescu For $n=1$ the permutations satisfying the desired conditions are (2,1,0), (0,1,2) (0,2,1), (1,2,0). The condition on the permutation involves only interior local maxima and minima.
Jan 20, 2012 at 16:08 history answered Karl Waugh CC BY-SA 3.0