Timeline for Independence of the axiomatics of metric cones
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Jan 19, 2012 at 21:03 | vote | accept | Larrieu | ||
Jan 19, 2012 at 21:03 | comment | added | Larrieu | OK you are right. This counter example is difficult to find. Did you know it before, or you managed to find it so quickly ? | |
Jan 19, 2012 at 18:59 | comment | added | Anton Petrunin | $d((1,0),(0,\tfrac12))=f(1,\tfrac12)=1$. So each term in the last sum is 1... | |
Jan 19, 2012 at 18:50 | comment | added | Larrieu | I'm afraid your counter example doesn't work. I have not checked all the axioms (in particular the fact that $d$ is a distance) but the calculus of the last line is wrong. It should be replaced by : $$d(a.x;b.y)+d(a'.x;b'.y) = \frac{3}{2} + \frac{1}{2}+\frac{3}{4} > d((a+a').x;(b+b').y).$$ I'm sorry. Nevertheless, your method for finding a counter example is a good one, I've been looking this way for quite a long without any success. | |
Jan 19, 2012 at 18:38 | vote | accept | Larrieu | ||
Jan 19, 2012 at 18:38 | |||||
Jan 19, 2012 at 18:38 | vote | accept | Larrieu | ||
Jan 19, 2012 at 18:38 | |||||
Jan 19, 2012 at 16:31 | history | answered | Anton Petrunin | CC BY-SA 3.0 |