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Sep 5, 2013 at 17:09 comment added Nate Eldredge Unless I am missing something, in a metric space (or any first countable space), shouldn't any sequence with a convergent subnet also have a convergent subsequence? So "subnet" here seems to be a red herring.
Jan 18, 2012 at 17:04 answer added Pietro Majer timeline score: 3
Jan 18, 2012 at 15:49 comment added Valerio Capraro Well, to exclude existence of convergent subsequences, it should be enough to take $x_n$ such that $d(x_n,x_m)=\frac{m−n}{n}$, for all $m\geq n$. It verifies the hypotheses above but has no Cauchy subsequences... subnets?
Jan 18, 2012 at 15:48 answer added Andreas Blass timeline score: 8
Jan 18, 2012 at 14:37 history asked Valerio Capraro CC BY-SA 3.0