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Timeline for Points on algebraic stacks

Current License: CC BY-SA 2.5

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Dec 11, 2009 at 21:25 comment added Mike Skirvin Thanks for the correction, Alberto. Looks like things were cleared up in the answer above, so I think I'm just going to leave my answer as is.
Dec 11, 2009 at 20:58 comment added Alicia Garcia-Raboso @Mike: Closed points do not necessarily have residue fields that are algebraically closed: e.g., Spec Z/p -> Spec Z is the a closed point, but Z/p is not algebraically closed!
Dec 11, 2009 at 19:05 comment added Mike Skirvin I agree that they must mean the closure.
Dec 11, 2009 at 19:04 comment added Daniel Larsson Although, come to think about it, why should closed points be defined as $Spec(K)$-valued points where $K$ is algebraically closed? This is not the case for schemes.
Dec 11, 2009 at 18:45 comment added Daniel Larsson Ok, I can buy this explaination, if that is what they mean. My main problem though was, given this, what is the $\{x\}$ and how can $y$ belong to this set (see 5.5). They must surely mean $\overline{\{x\}}$ (the closure)?
Dec 11, 2009 at 18:33 history answered Mike Skirvin CC BY-SA 2.5