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Jan 13, 2012 at 20:11 comment added Will Jagy Igor, this seems to be the induction step in your book's answer. I am still uncertain about graphs on $n$ vertices that are not complete, in $\mathbb R^{n-1}$ or possibly $R^{n-2}.$ Steve Carnahan feels that there is enough room in $\mathbb R^{n-1}$ to slightly perturb the positions of the balls (so as to erase edges from a complete graph and realize the graph we are actually given), perhaps keeping all radii the same. Note that we can do all graphs with 5 vertices in $\mathbb R^3,$ if not complete then planar, if complete then a regular tetrahedron with a smaller ball at center.
Jan 13, 2012 at 12:29 vote accept Joseph O'Rourke
Jan 13, 2012 at 12:25 history edited Joseph O'Rourke CC BY-SA 3.0
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Jan 13, 2012 at 9:21 comment added Igor Rivin Well, by Ian's argument, you can send two spheres to tangent hyperplanes, at which point you are asking if you can place a $K_{n-2}$ in $\mathbb{R}^{n-3},$ which you can, by the magic of regular simplices.
Jan 13, 2012 at 7:00 comment added Will Jagy I see, part (c) , page 191, answer page 395, exactly what Ian came up with. Do you think we can always place a graph with $n$ vertices in $\mathbb R^{n-2}?$
Jan 13, 2012 at 6:28 comment added Igor Pak Yeah, this is Exc. 20.12 (and a solution at the end) in my book math.ucla.edu/~pak/geompol8.pdf
Jan 13, 2012 at 6:12 comment added Will Jagy Also, $K_6$ cannot be a subgraph, from Ian's answer.
Jan 13, 2012 at 6:01 history answered Igor Pak CC BY-SA 3.0