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Kevin O'Bryant
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If thereThere are exactly twoat most 2 groups (up to isomorphism) of order $n$, thenand there is not a field of order $n$, if and only if $n$ is the product of two distinct primes.

This isn't if and only if, it doesn't capture "distinct", and it doesn't cover "prime powers", but at least it's nontrivial.

If there are exactly two groups (up to isomorphism) of order $n$, then $n$ is the product of two primes.

This isn't if and only if, it doesn't capture "distinct", and it doesn't cover "prime powers", but at least it's nontrivial.

There are at most 2 groups (up to isomorphism) of order $n$, and there is not a field of order $n$, if and only if $n$ is the product of two distinct primes.

This doesn't cover "prime powers", but at least it's nontrivial.

Source Link
Kevin O'Bryant
  • 9.8k
  • 6
  • 57
  • 84

If there are exactly two groups (up to isomorphism) of order $n$, then $n$ is the product of two primes.

This isn't if and only if, it doesn't capture "distinct", and it doesn't cover "prime powers", but at least it's nontrivial.