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Jan 6, 2012 at 15:09 comment added Andreas Blass Apologies to Michael for my error, and thanks to Andres for correcting it.
Jan 6, 2012 at 3:51 comment added Andrés E. Caicedo See also mathoverflow.net/questions/26861/… where I explain why ${\mathcal P}({\mathbb R})$ lacks a linear ordering in some well studied models of set theory without choice.
Jan 6, 2012 at 3:47 history edited Andrés E. Caicedo CC BY-SA 3.0
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Jan 6, 2012 at 0:40 comment added expmat That's true... :)
Jan 5, 2012 at 23:20 comment added Michael Greinecker Uhm...it's Michael, actually. :-)
Jan 5, 2012 at 23:01 vote accept expmat
Jan 5, 2012 at 22:28 history answered Andreas Blass CC BY-SA 3.0