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May 20, 2012 at 6:17 vote accept SadeghD
Jan 7, 2012 at 19:28 history edited Benjamin Young CC BY-SA 3.0
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Jan 7, 2012 at 12:56 comment added SadeghD Yes, being uncountable contradicts with being finite. I correct myself. X is infinite but because of being uncountable, not because of having infinite bounds. Besides that, the question looks to have an answer. Is Mobius representation of a set function restricted to finite sets?
Jan 7, 2012 at 11:46 comment added Benjamin Young That doesn't make sense I'm afraid...
Jan 7, 2012 at 8:48 comment added SadeghD I edited my question, and clarified that I want X to be uncountable, but finite.
Jan 5, 2012 at 9:57 history answered Benjamin Young CC BY-SA 3.0