I think in order to answer this usefully(edit) Okay, we need more details about whatso as far as i can see you want to do. Which pieces offind a replacement for the formula do you wantmobius transform, but for a $\sigma$-algebra. In fact I'm going to be continuousguess that your $\sigma$-algebra is the measurable sets in the unit interval, andbased on what you've said.
The most general setting I know of in which you can stay discrete? Is there an easydefine a Möbius function is a locally finite, partially ordered set (see, for example which you could include?, http://en.wikipedia.org/wiki/Incidence_algebra). So it sounds like you're out of luck. The measurable sets definitely don't form a locally finite poset.
At the bare minimumHowever, I really don't think you've asked the right question yet. You probably would get better answers than mine if $X$ isn't finiteyou frame your question in terms of measure theory, then you'll have to replacerather than Möbius inversion. For instance, the power setwikipedia article seems to imply that I should think of $X$Möbius inversion as "analagous to differentiation", and convolution with something else in orderthe zeta function as "analagous to make any senseintegration". I don't really find this too helpful, but that's what it says. Maybe you're looking for some kind of that sumderivative? Just a guess.