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Jan 1, 2012 at 17:46 comment added Mahdi Majidi-Zolbanin As Graham's example shows, it's not true in general, but sometimes it's true. For example if $A$ is a domain and $M$ is finitely generated, then it's true, because if $M$ is maximal CM, then $\mathrm{dim}\ M = \mathrm{depth}\ M = \mathrm{dim}\ A$. If $I$ is the annihilator of $M$, then it follows $\mathrm{dim}\ A/I=\mathrm{dim}\ A$. Then since $A$ is a domain, $I=(0)$, and since $M$ is finitely generated, $\mathrm{Supp}(M)=V(I)=\mathrm{Spec}\:A$.
Jan 1, 2012 at 17:29 vote accept ashpool
Jan 1, 2012 at 17:14 vote accept ashpool
Jan 1, 2012 at 17:26
Jan 1, 2012 at 16:58 answer added Graham Leuschke timeline score: 3
Jan 1, 2012 at 15:43 history asked ashpool CC BY-SA 3.0