Timeline for The Classifying Space of the Discrete Heisenberg Group
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 18, 2012 at 13:19 | vote | accept | Zuriel | ||
| Apr 18, 2012 at 13:19 | |||||
| Jan 1, 2012 at 5:05 | comment | added | Andy Putman | @Vitali : Thanks for the correction! I've been celebrating the new year, so I'm pretty happy I managed to at least put the word "connected" in all the right places... | |
| Jan 1, 2012 at 5:04 | history | edited | Andy Putman | CC BY-SA 3.0 |
added 17 characters in body
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| Jan 1, 2012 at 4:20 | comment | added | Vitali Kapovitch | @Tom Church Oops, I guess the standard definition of a lattice requires finite volume of the quotient. Then cocompactness is of course automatic for nilpotent groups. I've often had to work with discrete noncocompact subgroups of nilpotent Lie groups which I often also call lattices but I guess that's wrong terminology. | |
| Jan 1, 2012 at 3:57 | comment | added | Tom Church | @Mark: all lattices in nilpotent Lie groups are cocompact. | |
| Jan 1, 2012 at 3:06 | comment | added | Vitali Kapovitch | @Mark: yes, the standard definition of the Malcev completion requires that $\Gamma$ is cocompact in $G$. This also makes Malcev completion unique. @Andy, I think you wanted to say that a simply connected nilpotent Lie group is diffeomorphic to $\mathbb R^n$. | |
| Jan 1, 2012 at 2:40 | comment | added | Mark | A question: will $\Gamma$ generally be a uniform (cocompact) lattice in $G$? | |
| Jan 1, 2012 at 2:22 | history | answered | Andy Putman | CC BY-SA 3.0 |