Skip to main content

Timeline for gcd of three numbers

Current License: CC BY-SA 3.0

12 events
when toggle format what by license comment
Jan 1, 2012 at 0:46 vote accept user3208
Dec 31, 2011 at 8:41 answer added Aaron Meyerowitz timeline score: 0
Dec 31, 2011 at 7:33 comment added Gerhard Paseman AH: Given $\epsilon>0$, there is (I believe an effectively computable) $N$ such that for all $n > N$, the desired $O(n^\epsilon)$ result holds: see the question answer by The Hamburglar and my comments regarding explicit bounds on Jacobsthal's function. Gerhard "Ask Me About System Design" Paseman, 2011.12.30
Dec 31, 2011 at 6:39 answer added user631 timeline score: 8
Dec 30, 2011 at 1:53 comment added user3208 @AH, could you give me the reference to your paper? No I do not have a proof. A heuristic argument indicates the bound can be as small as $(\log n)^{O(1)}$, but I have yet to turn it into a rigorous proof.
Dec 29, 2011 at 22:23 comment added Alan Haynes ...the only reason I am asking is that one of my coauthors and I came across the same problem one time and we ended up settling for something which met our need but was quite a bit weaker than what you are reporting.
Dec 29, 2011 at 22:11 comment added Alan Haynes @Qi Just for clarification, were you implying that you already have a proof?
Dec 29, 2011 at 19:03 comment added user3208 That is right. $|c|$ and $|d|$ should be bounded above.
Dec 29, 2011 at 18:11 comment added Kevin O'Bryant You must mean that $|c|$ and $|d|$ can be bounded above? I ask because you emphasize the positivity of $a,b,n$, but notably not these others...
Dec 29, 2011 at 17:51 comment added user3208 Yes it is an absolute constant
Dec 29, 2011 at 17:08 comment added GH from MO Is your $O(1)$ an absolute constant (not depending on $a$ and $b$)?
Dec 29, 2011 at 16:41 history asked user3208 CC BY-SA 3.0