Timeline for do spectra have diagonal maps?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 7, 2012 at 16:18 | vote | accept | Cary | ||
| Jan 1, 2012 at 15:42 | comment | added | Tom Goodwillie | Yes. I have edited to clarify this. | |
| Jan 1, 2012 at 15:41 | history | edited | Tom Goodwillie | CC BY-SA 3.0 |
added 472 characters in body
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| Jan 1, 2012 at 15:28 | comment | added | Cary | So if I had a natural "diagonal" $X \rightarrow X \wedge X$ then it would give a bilinear pairing $[X,A] \times [X,B] \rightarrow [X,A \wedge B]$. By your argument, such a pairing must be zero. So the only candidate for $X \rightarrow X \wedge X$ is the zero map. Did I understand that correctly? | |
| Jan 1, 2012 at 15:18 | vote | accept | Cary | ||
| Jan 1, 2012 at 15:23 | |||||
| Dec 28, 2011 at 18:30 | history | answered | Tom Goodwillie | CC BY-SA 3.0 |