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Dec 23, 2011 at 17:33 vote accept Guillaume Brunerie
Dec 23, 2011 at 14:00 history edited Jonathan Chiche CC BY-SA 3.0
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Dec 22, 2011 at 14:59 comment added Jonathan Chiche Je t'en prie ! (Excuse my French.) I should have made clear that I addressed only the first point (the answer to which is standard), sorry about that. The second one is indeed trickier (see Charles Rezk's answer).
Dec 22, 2011 at 14:28 comment added Chris Schommer-Pries "is it automatic W satisfies 2 out of 3?", ahh no. You caught me! You need that too. It looks like Rezk's answer has another characterization.
Dec 22, 2011 at 14:15 comment added Guillaume Brunerie Thanks Jonathan! Chris, is it automatic that this $W$ satisfies 2 out of 3?
Dec 22, 2011 at 14:08 comment added Chris Schommer-Pries Just to clarify to Jonathan's answer, if there exists such a model structure, then the weak equivalences are exactly those arrows which are composites of an arrow in $C_W$ followed by an arrow in $F_W$. So there is at most one such model structure. Moreover, let this define the class W. Then your factorizations systems give you a model structure precisely if $F_W = W \cap F$ and similarly for $C_W$.
Dec 22, 2011 at 13:48 history answered Jonathan Chiche CC BY-SA 3.0