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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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Dec 20, 2011 at 2:58 vote accept Ehsan M. Kermani
Dec 20, 2011 at 1:35 answer added Benjamin Steinberg timeline score: 5
Dec 20, 2011 at 1:24 comment added Benjamin Steinberg Richard, he said H is torsion-free so in particular not finite.
Dec 20, 2011 at 1:23 comment added Benjamin Steinberg Doesn't the answer to Florent's question answer yours? The acc implies finitely generated and by the answer to that question all fg images are finite.
Dec 20, 2011 at 1:22 comment added Autumn Kent If $G$ is finite, it's false. So I guess you should take $G$ infinite. Do you want to show that there is no injective homomorphism $G \to H$? Because then you just need to show that $G$ fails to have the ascending condition. Hint: $G$ is uncountable. If that isn't what you mean, then take $G$ profinite and let $H$ be a finite quotient. Or am I missing something?
Dec 20, 2011 at 1:10 history asked Ehsan M. Kermani CC BY-SA 3.0