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Jul 21, 2014 at 14:19 history edited David White CC BY-SA 3.0
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Oct 17, 2009 at 12:13 comment added Tyler Lawson That's right, and that works much more cleanly. Note G doesn't need to be discrete for these arguments.
Oct 17, 2009 at 7:20 comment added Reid Barton Thanks. Seems the key is the fibration U -> U_hG -> BG which I hadn't considered. You can use it to give a proof that doesn't need any algebra: consider the 3x3 square diagram with rows [, BG, X_hG], [, BG, Z_hG], [*, BG, Y_hG], and all maps pointing "inward"; taking horizontal homotopy pullbacks commutes with taking vertical homotopy pullbacks.
Oct 17, 2009 at 7:15 vote accept Reid Barton
Oct 17, 2009 at 5:09 history answered Tyler Lawson CC BY-SA 2.5