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Michael Albanese
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I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: (1,1),(2,1),...,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).$$(1,1),(2,1),\dots,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).$$

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1, 0] [2, 1]]$ and $[[1, 2][2, 5]]$ are listed as different cosets representatives, but

\[ \begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}=\begin{pmatrix} 1 & 2 \\ 2 & 5 \end{pmatrix} \]$$\begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}=\begin{pmatrix} 1 & 2 \\ 2 & 5 \end{pmatrix}$$

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.

I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: (1,1),(2,1),...,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1, 0] [2, 1]]$ and $[[1, 2][2, 5]]$ are listed as different cosets representatives, but

\[ \begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}=\begin{pmatrix} 1 & 2 \\ 2 & 5 \end{pmatrix} \]

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.

I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: $$(1,1),(2,1),\dots,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).$$

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1, 0] [2, 1]]$ and $[[1, 2][2, 5]]$ are listed as different cosets representatives, but

$$\begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}=\begin{pmatrix} 1 & 2 \\ 2 & 5 \end{pmatrix}$$

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.

Rewrote the matrices to be clearer (I did not understand them at all beforehand)
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Max Horn
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I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: (1,1),(2,1),...,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1 0] [2 1]]$$[[1, 0] [2, 1]]$ and $[[1 2][2 5]]$$[[1, 2][2, 5]]$ are listed as different cosets representatives, but

\begin{equation} [[1 0] [2 1]] \cdot [[1 2][0 1]]=[[1 2][2 5]] \end{equation}\[ \begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}=\begin{pmatrix} 1 & 2 \\ 2 & 5 \end{pmatrix} \]

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.

I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: (1,1),(2,1),...,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1 0] [2 1]]$ and $[[1 2][2 5]]$ are listed as different cosets representatives, but

\begin{equation} [[1 0] [2 1]] \cdot [[1 2][0 1]]=[[1 2][2 5]] \end{equation}

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.

I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: (1,1),(2,1),...,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1, 0] [2, 1]]$ and $[[1, 2][2, 5]]$ are listed as different cosets representatives, but

\[ \begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}=\begin{pmatrix} 1 & 2 \\ 2 & 5 \end{pmatrix} \]

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.

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Nick
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Cosets representatives of congruence subgroups

I came across Shimura (1971) notes about cosets representatives of the congruence subgroups $ \Gamma_0(N) $. He firstly proves that its index in the modular group $\Gamma$ is

\begin{equation} [\Gamma : \Gamma_0(N)]=N \cdot \prod_{p|N} (1+p^{-1} ) \end{equation}

Then he comes up with a sets of cosets representatives for $\Gamma_0(N)$ in $\Gamma$ made in this way: we first choose pairs $(c,d)$ of positive integers such that

\begin{equation} (c,d)=1, \qquad d|N, \qquad 0 < c \le N/d \end{equation}

then for each pairs we fix integers $a,b$ such that $ad-bc=1$. Our list of cosets representatives is made of the matrices with such entries.

However, let us take for example $N=12$ when we know the index is 24 and thus this is the cardinality of the set of cosets representatives. Using the rule above, I only find 22 cosets representatives, namely the ones corresponding to the following $(c,d)$ pairs: (1,1),(2,1),...,(12,1),(1,2),(3,2),(5,2),(1,3),(2,3),(4,3),(1,4),(3,4),(1,6),(1,12).

I also tried to run SAGE and it gives me 24 cosets representatives but they seem redundant, for example $[[1 0] [2 1]]$ and $[[1 2][2 5]]$ are listed as different cosets representatives, but

\begin{equation} [[1 0] [2 1]] \cdot [[1 2][0 1]]=[[1 2][2 5]] \end{equation}

and thus it seems to me that these 2 matrices belong in fact to the same coset.

Something is clearly wrong, I hope you can help me.