I have come across an interesting property of a dynamical system, being transformed by a map, but i haven't been able to figure out why this is happening (for quite some time now actually). Any help is greatly appreciated. Here goes then:
Let M be a n-D manifold and $\dot x=F(x)u_1, F\in \mathbb{R}^{n\times m}, u_1 \in \mathbb{R}^{m}$$\dot x=F(x)u_1, F\in \mathbb{R}^{n\times m}, x \in \mathbb{R}^{n}, u_1 \in \mathbb{R}^{m}$ be a control system evolving on M (F is the system matrix i.e. state transition function, and $u_1$ is the input of the system. For all practical purposes $u_1$ is an m-vector from an input space $\mathbb{R}^{m}$). Now let $x=\Psi (y)$ be a coordinate change on M and $u_2=M(y)u_1$ a transformation of the input $u_1$ of the first system. By applying these maps on the system, you get the new equations $\dot y=F(y)u_2$. As you may notice, F is the same in both systems. The problem is why is this happening i.e. for what systems and transformations does this property hold?
A little more elaboration
It is useful to investigate the maps more closely. In the general case one has
$\dot x=D\Psi \dot y$
$\dot x= F(x)u_1$
thus
$\dot y=D\Psi ^{-1} F(x)u_1$, (1)
where $D\Psi$ is the Jacobian matrix of $\Psi$. In our case it actually turns out that:
$\dot y=F(y)M(y)u_1$. (2)
You can then consider that $u_2=M(y)u_1$ and get the final system,
$\dot y=F(y)u_2$,
that is, the same system. By (1),(2) you get,
$D\Psi ^{-1} F(x)u_1=F(y)M(y)u_1 \Rightarrow (D\Psi ^{-1} F(x)-F(y)M(y))u_1=0$.
Since this holds for every $u_1$, you have the condition,
$F(\Psi (y))=D\Psi F(y)M(y)$
So, what does this condition imply? What systems F and maps $\Psi$ hold this property (of system invariance)? I should note that F is nonlinear and a case study where this actually happens is the kinematic model of a unicycle robot i.e. this. Any ideas?