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Dec 17, 2011 at 18:19 vote accept zroslav
Dec 17, 2011 at 17:00 comment added Benjamin Steinberg Actually for algebraically closed fields it is Burnside's theorem of which Jacobson's theorem is a generalization.
Dec 17, 2011 at 15:48 comment added darij grinberg Because it's called Jacobson's density theorem. Check Theorem 2.5 (a) in arxiv.org/abs/0901.0827 for a proof.
Dec 17, 2011 at 15:15 comment added zroslav Why this is true for algebraically closed field?
Dec 17, 2011 at 14:24 history answered Vladimir Dotsenko CC BY-SA 3.0