I am sorry: my previous posts were incorrect, I will correct below.
I would suggest you guys insert the statement and may be proof to Wiki article,
it is quite worth and since it was mainly written by me, imho I might give such a suggestion.
ThereThe main message is a relationthat there is "certain relation" (described below) between JM in S_n andstandard Gelfand-Tsetlin maximal commutative subalgebra in U(gl). JM$U(gl_N)$ and the maximal commutative subalgebra in $C[S_N]$ generated by Jucys-Murphy elements will.
The relation consists of two steps which can be mapped into quadratic Casimir operatorsseen as generalized Schur-Weyl duality and generalized $gl_M - gl_N$ duality.
Both steps involves an intermediate object - "bending flow" commutative in $U(gl_N \oplus ... \oplus gl_N)$ (if I remember correctly, not suresum contains $M$ terms), so it might be possible to get the answer.
Briefly speaking these generalized dualities say
that: images in this way, although, itcertain representations of these commutative subalgebras coincide.
Since I forget some details I would NOT bemake again the shortest one:claim that "JM elements go to "quadratic Casimirs"", which might give another (but very long) Butway to answer Igor's question. Just simply describe the dualities aboverelation which might be of interestinteresting on theirits own. Consider representation of S_n in $V\oplus ... V$, JM gives commutative subalgebra there.
RemarkStep 1. It is interestingGeneralized Schur-Weyl from JM to mention that in case V=R^3 it is the same as "bending flows" integrable system - very nice thing - bending the polygon along non intersecting diagonals you see a set of commuting hamiltonians on the moduli space of polygons...
Commutativity is obvious from the geometry, lemma is to show that we get JM(Rather trivial step).
Return to JM: consider $V=C^k$ soConsider $V\oplus ... \oplus V = C^k \otimes C^n$.
The point is that if one considers representation of$V=C^N \otimes ... \otimes C^N$ $U(gl_k)$($M$ terms in tensor product). $C^k \otimes C^n$ then image of Gelfand-Tsetlin subalgebra$C[S_M]$
acts here in a natural way. $U(gl_k)$ will coincide with JM image$U(gl_N \oplus ... \oplus gl_N)$ surjects on $End(V)$.
This was first observed by Flashka and Millson. Another treatment is givenSince it surjects we can find certain elements in our paper: $U(gl_N \oplus ... \oplus gl_N)$
http://arxiv.org/abs/0710.4971
Our point waswhich are mapped to show that JM and bending flows are limit of the so-called Gaudin commutative subalgebraelements, moreover we require such elements to be quadratic in generators of $U(gl_n)\otimes ... \otimes U(gl_n)$$U(gl_N \oplus ... \oplus gl_N)$, which is interesting from variaous points of view from Langlands to Bethe ansatzand it would fix these elements. Since we know that spectrum of JM
The basic idea is simple we can conclude that spectrum of Gaudin is simplethe permutation operator (12) acting in certain cases $C^N\otimes C^N$ is OBVIOUSLY an image of $\sum_{ij} E_{ij}\otimes E_{ji} \in U(gl_N)\otimes U(gl_N)=U(gl_N\oplus gl_N)$ and nothing more than that.
[EDIT]
@Darij
"JM elements will be mapped into quadratic Casimir operators".
By what?
By $E_{ij}$ denoted the construction I tried to described below. I will try to describe it more clearer againmatrix with $1$ at position $(ij)$ and happy to answer any questions..zeros everywhere else.
Schur-Weyl duality?
No it is notSo we get certain commutative subalgebra in
$U(gl_N \oplus ... \oplus gl_N)$ such that simple. Itit is composition of Shur"Schur-Weyl with GL_n-GL_m dualities, but both are being generalized from their classical formdual" to more strong statementsJM subalgebra,
meaning that the images of these subalgebras in $End(V)$ coincide.
How exactly?
Let me tryStep 2. $GL_M-GL_N$-duality from "bending flows" to say it again:Gelfand-Tsetlin.
(This step is not so trivial).
It is mainly due to Flaschka and Millson - section 8 of
http://arxiv.org/abs/math.SG/0108191
Consider representation of $gl_k$ in $C^k\otimes C^n$ (where we act only the firstvector space). Consider the representation of $S_n$ in the $C^k\oplus ... \oplus C^k$$W = S(C^N\otimes C^M) = S(C^N \oplus ... \oplus C^N)$ (here $n$M-times is summedterms in sum). Note that there is isomorphism and $S$ denotes symmetric algebra of the vector spaces: $C^k\otimes C^n = C^k\oplus ... \oplus C^k$space.
So we see that twoLie algebras $U(gl_k)$$gl_M$ and $S_n$ act$U(gl_N \oplus ... \oplus gl_N)$ acts on the same vector space
$C^k\otimes C^n = C^k\oplus ... \oplus C^k$$W$ in a natural way.
Fact 1. The image in $End( C^k\otimes C^n ) $ ofTheorem: the JM commutative subalgebraimages in $S_n$
coincide with the image$End(V)$ of GT in the same spaceand "bending flows" coincide.
Is this formulation clear ?In such a form it is Theorem 2 page 9 in our paper:
http://arxiv.org/abs/0710.4971
The fact above was aboutWhy the subalgebrasname "bending flows" (i.e. vector spaces),?
If we might want to askmake similar considerations for more strong fact - take some particular element in JM subalegbra i.e. $X_k$ and ask$U(so_3 \oplus ... \oplus so_3)$
what is the particular element in GT such the their images coincide under the representations aboveor more precisely its associated grade Poisson algebra
$S(so_3 \oplus ... \oplus so_3)$ we get a ?(Poisson) commutative subalgebra there.
"quadratic Casimir" - means the quadratic element of the center of U(gl), itThe beautiful fact is not unique, but almost unique: any such elementthat "JM" type generators have formvery nice geometric interpretation.
We can identify $a C_2 + b C_1^2$, where a,b are complex numbers$so_3=R^3$ and so elements of $C_1$$(so_3 \oplus ... \oplus so_3)$
can be seen as $M$- generator of the center of gl itselfgons in (i.e$R^3$. identity matrix) and $C_2$
The statement is any quadratic generator ofthat if we "bend" polygon along the center.
As far as I rememeber one should take quadratic Casimirs in GT of U(gl_k)non-intersecting diagonals
then such flows will be hamiltonian and "they will be mapped intodefined by JM elements X_l" (meaning that the images of these elements will coincide under representations above)-type generators in
$S(so_3 \oplus ... \oplus so_3)$. How to fix "a
Well,b" I doomitted some details and may be comment is not rememberso clear,
one should draw simple pictures in order to see what is going on.
Bending flows were proposed for $S(so_3 \oplus ... \oplus so_3)$
in paper M. Kapovich, J. Millson, The point is that the number $l$ in index of JM element $X_l$ will be the same as indexsymplectic geometry of polygons in Euclidean space,J. Differ. Geom. 44, 479–513 $gl$ subalgebra(1996)
Generalized further in $gl_l \in gl_n$ in construction of GT subalgebraseveral papers in Uparticular in
Gregorio Falqui, Fabio Musso, Gaudin Models and Bending Flows: a Geometrical Point of View, J. Phys. A 36 (gl_k2003),
no. 46,11655–11676. nlin.SI/0306005
Is the claim clear ?http://arxiv.org/abs/nlin/0306005