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Dec 16, 2011 at 23:32 vote accept Alan Haynes
Dec 16, 2011 at 15:49 comment added Alan Haynes @Vitali Ok thanks for the update, I was starting to think that maybe I had overlooked something obvious.
Dec 16, 2011 at 15:30 comment added Vitali Kapovitch @Gerald sorry, you are quite right.
Dec 16, 2011 at 15:12 comment added Gerald Edgar Hausdorff measure is unfortunately not multiplicative for metric spaces in general. But in this case (self-similar factors) we have more information. So Anthony's proof has a chance of working.
Dec 16, 2011 at 14:05 answer added Anthony Quas timeline score: 2
Dec 16, 2011 at 10:54 history asked Alan Haynes CC BY-SA 3.0