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Dec 15, 2011 at 14:00 comment added Julien Marché I agree with Guillaume, the attaching map from the boundary of the 2-cells to the figure-eight can be anything, so your assumption is too strong. To Ralph, $\pi_2(X)$ is always commutative and by Hurewicz's theorem, if $\pi_1(X)=1$, then the map $\pi_2(X)\to H_2(X)$ is an isomorphism, showing the result. Of course, one cannot suppose that $\pi_1(X)=1$!
Dec 15, 2011 at 13:33 comment added Ralph I wonder about $H_2(X) = Ab \pi_2(X)$: Isn't the second (and higher) homotopy group always abelian ? I only know this formula in degree one, does it also hold in degree 2 ? (I don't know much about topology, so I my be wrong.)
Dec 15, 2011 at 13:14 comment added Guillaume Brunerie A 2-cell can be attached to some interlacing of both loops (the fundamental group of the figure-8 is free on the two generators that are the two loops).
Dec 15, 2011 at 13:07 history answered Mikael Vejdemo-Johansson CC BY-SA 3.0