Timeline for What does "linearly disjoint" mean for abstract field extensions?
Current License: CC BY-SA 2.5
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Dec 9, 2009 at 16:12 | history | edited | Andrew Critch | CC BY-SA 2.5 |
basically added some dollar signs
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Dec 9, 2009 at 8:06 | comment | added | user2035 | k(t) ⊗ k(t) is indeed not a field, the kernel I of the multiplication map to k(t) is non-trivial (I/I² is Kahler differentials). | |
Dec 9, 2009 at 7:56 | history | answered | Pete L. Clark | CC BY-SA 2.5 |