Timeline for Solve |\nabla u|^2=1
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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Dec 13, 2011 at 10:18 | vote | accept | Mahdiyar | ||
Dec 13, 2011 at 10:10 | comment | added | Mahdiyar | Thanks Robert. I guess you meant $F'=f$ not $=1/f$. I would've picked this as my answer if it were not a comment. | |
Dec 13, 2011 at 6:16 | answer | added | Denis Serre | timeline score: 2 | |
Dec 12, 2011 at 20:10 | answer | added | Rebs | timeline score: 2 | |
Dec 12, 2011 at 20:01 | comment | added | Robert Bryant | @Mahdiyar: Look up the literature on the eikonal equation, which this is. There, you will see that the `general solution' is to let $u(x,y)$ be a constant plus the (signed) distance of $(x,y)$ to some set (usually a point or a curve) in the plane. The only global smooth solutions are linear functions (as you gave), and the only global solution with only one singular point is the distance from a point (plus constants), as you saw. For the more general case, as long as $f$ is strictly positive, you let $u = F(v)$ where $v$ satisfies the original equation ($f\equiv1$) and $F'(v) = 1/f(F(v))$. | |
Dec 12, 2011 at 19:45 | history | asked | Mahdiyar | CC BY-SA 3.0 |